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Lesson 13:

Sedimentation Basin Design and Problems

Designing a Rectangular Sedimentation Tank

Introduction

Designing a rectangular sedimentation tank is similar in many ways to designing a flocculation

chamber.However, water in a sedimentation basin is not agitated, so the velocity gradient is not

a factor in the calculations. Instead, two additional characteristics are important in designing a

sedimentation basin.

The overflow rate (also known as the surface loading or the surface overflow rate) is equal to

the settling velocity of the smallest particle which the basin will remove. Surface loading is

calculated by dividing the flow by the surface area of the tank.Overflow rate should usually be

less than 1,000 gal/day-ft.2

The weir loading is another important factor in sedimentation basin efficiency.Weir loading,

also known as weir overflow rate, is the number of gallons of water passing over a foot of weir

per day. The standard weir overflow rate is 10,000 to 14,000 gpd/ft and should be less than

20,000 gpd/ft.Longer weirs allow more water to flow out of the sedimentation basin without

exceeding the recommended water velocity.

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Specifications

The sedimentation basin we will design in this lesson will be a rectangular sedimentation basin

with the following specifications:

• Rectangular basin

• Depth: 7-16 ft

• Width: 10-50 ft

• Length: 4 × width

• Influent baffle to reduce flow momentum

• Slope of bottom toward sludge hopper >1%

• Continuous sludge removal with a scraper velocity <15 ft/min

• Detention time: 4-8 hours

• Flow through velocity: <0.5 ft/min

• Overflow rate: 500-1,000 gal/day-ft2

• Weir loading: 15,000-20,000 gal/day-ft

Overview of Calculations

We will determine the surface area, dimensions, and volume of the sedimentation tank as well as

the weir length. The calculations are as follows:

1. Divide flow into at least two tanks.

2. Calculate the required surface area.

3. Calculate the required volume.

4. Calculate the tank depth.

5. Calculate the tank width and length.

6. Check flow through velocity.

7. If velocity is too high, repeat calculations with more tanks.

8. Calculate the weir length.

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1. Divide the Flow

The flow should be divided into at least two tanks and the flow through each tank should be

calculated using the formula shown below:

Qc = Q / n

Where:

Qc = flow in one tank

Q = total flow

n = number of tanks

We will consider a treatment plant with a flow of 1.5 MGD.We will divide the flow into three

tanks, so the flow in one tank will be:

Qc = (1.5 MGD) / 3

Qc = 0.5 MGD

2. Surface Area

Next, the required tank surface area is calculated.We will base this surface area on an overflow

rate of 500 gal/day-ft2 in order to design the most efficient sedimentation basin.

The surface area is calculated using the following formula:

A = Qc / O.R.

Where:

A = surface area, ft2

Qc = flow, gal/day

O.R. = overflow rate, gal/day-ft2

In our example, the surface area of one tank is calculated as follows:

A = (500,000 gal/day) / (500 gal/day-ft2)

A = 1,000 ft2

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(Notice that we converted the flow from 0.5 MGD to 500,000 gal/day before beginning our

calculations.)

3. Volume

The tank volume is calculated just as it was for flocculation basins and flash mix chambers, by

multiplying flow by detention time. The optimal detention time for sedimentation basins

depends on whether sludge removal is automatic or manual.When sludge removal is manual,

detention time should be 6 hours.We will consider a tank with automatic sludge removal, so the

detention time should be 4 hours.

The volume of one of our tanks is calculated as follows:

V = Q t

V = (500,000 gal/day) (4 hr) (1 day/24 hr) (1 ft3/7.48 gal)

V = 11,141 ft3

(Notice the conversions between days and hours and between cubic feet and gallons.)

4. Depth

The tank's depth is calculated as follows:

d = V / A

Where:

d = depth, ft

V = volume, ft3

A = surface area, ft2

For our example, the depth is calculated to be:

d = (11,141 ft3) / (1,000 ft2)

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d = 11.1 ft

The specifications note that the depth should be between 7 and 16 feet.Our calculated depth is

within therecommended range.If the depth was too great, we would begin our calculations

again, using a larger number of tanks.If the depth was too shallow, we would use a smaller

number of tanks.

5. Width and Length

You will remember that the volume of a rectangular solid is calculated as follows:

V = L W d

Where:

V = volume

L = length

W = width

d = depth

For our tank, the length has been defined as follows:

L = 4 W

Combining these two formulas, we get the following formula used to calculate the width of our

tank:

In the case of our example, the tank width is calculated as follows:

W = 15.8 ft

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The length is calculated as:

L = 4 (15.8 ft)

L = 63.2 ft

6 and 7. Flow Through Velocity

Checking the flow through velocity is done just as it was for the flocculation basin.First, the

cross-sectional area of the tank is calculated:

Ax = W d

Ax = (15.8 ft) (11.1 ft)

Ax = 175.4 ft

2

Then the flow through velocity of the tank is calculated (with a conversion from gallons to cubic

feet and from days to minutes):

V = Qc / Ax

V = (0.0000928 ft3-day/gal-min) (500,000 gal/day) / (175.4 ft2)

V = 0.26 ft/min

The velocity for our example is less than 0.5 ft/min, so it is acceptable.As a result, we do not

need to repeat our calculations.

8. Weir Length

The final step is to calculate the required length of weir.We will assume a weir loading of

15,000 gal/day-ft and use the following equation to calculate the weir length:

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Lw = Qc / W.L

Where:

Lw = weir length, ft

Qc = flow in one tank, gal/day

W.L. = weir loading, gal/day-ft

So, in our example, the weir length is calculated as follows:

Lw = (500,000 gal/day) / (15,000 gal/day-ft)

Lw = 33.3 ft

The weir length should be 33.3 ft.

Conclusions

Our plant should build a sedimentation tank which is 11.1 feet deep, 15.8 feet wide, and 63.2 feet

long. This tank will have a surface area of 1,000 ft2 and a volume of 11,141 ft3. The flow

through velocity will be 0.26 ft/min. Theweir length will be 33.3 ft.

Review

Sedimentation basin efficiency is influenced by floc characteristics, water temperature, short-

circuiting, gases in the water, algal growth on tank walls, intermittent tank operation, surface

loading, and weir loading. To ensure optimal performance, the operator should test turbidity and

temperature of the water and should visually survey the basin

Design of a sedimentation basin involves the following steps:

· Divide flow into at least two tanks.

· Calculate the required surface area.

· Calculate the required volume.

· Calculate the tank depth.

· Calculate the tank width and length.

· Check flow through velocity.

· If velocity is too high, repeat calculations with more tanks.

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· Calculate the weir length.

New Formulas Used

To calculate tank surface area:

A = Qc / O.R.

To calculate tank depth:

d = V / A

To calculate width of a rectangular tank where length is four times the width:

To calculate length of a rectangular tank where length is four times the width:

L = 4 W

To calculate flow through velocity:

V = Qc / Ax

To calculate weir length:

Lw = Qc / W.L

Lesson 13:

Sedimentation Basin Design and Problems

Designing a Rectangular Sedimentation Tank

Introduction

Designing a rectangular sedimentation tank is similar in many ways to designing a flocculation

chamber.However, water in a sedimentation basin is not agitated, so the velocity gradient is not

a factor in the calculations. Instead, two additional characteristics are important in designing a

sedimentation basin.

The overflow rate (also known as the surface loading or the surface overflow rate) is equal to

the settling velocity of the smallest particle which the basin will remove. Surface loading is

calculated by dividing the flow by the surface area of the tank.Overflow rate should usually be

less than 1,000 gal/day-ft.2

The weir loading is another important factor in sedimentation basin efficiency.Weir loading,

also known as weir overflow rate, is the number of gallons of water passing over a foot of weir

per day. The standard weir overflow rate is 10,000 to 14,000 gpd/ft and should be less than

20,000 gpd/ft.Longer weirs allow more water to flow out of the sedimentation basin without

exceeding the recommended water velocity.

Page 2

Specifications

The sedimentation basin we will design in this lesson will be a rectangular sedimentation basin

with the following specifications:

• Rectangular basin

• Depth: 7-16 ft

• Width: 10-50 ft

• Length: 4 × width

• Influent baffle to reduce flow momentum

• Slope of bottom toward sludge hopper >1%

• Continuous sludge removal with a scraper velocity <15 ft/min

• Detention time: 4-8 hours

• Flow through velocity: <0.5 ft/min

• Overflow rate: 500-1,000 gal/day-ft2

• Weir loading: 15,000-20,000 gal/day-ft

Overview of Calculations

We will determine the surface area, dimensions, and volume of the sedimentation tank as well as

the weir length. The calculations are as follows:

1. Divide flow into at least two tanks.

2. Calculate the required surface area.

3. Calculate the required volume.

4. Calculate the tank depth.

5. Calculate the tank width and length.

6. Check flow through velocity.

7. If velocity is too high, repeat calculations with more tanks.

8. Calculate the weir length.

Page 3

1. Divide the Flow

The flow should be divided into at least two tanks and the flow through each tank should be

calculated using the formula shown below:

Qc = Q / n

Where:

Qc = flow in one tank

Q = total flow

n = number of tanks

We will consider a treatment plant with a flow of 1.5 MGD.We will divide the flow into three

tanks, so the flow in one tank will be:

Qc = (1.5 MGD) / 3

Qc = 0.5 MGD

2. Surface Area

Next, the required tank surface area is calculated.We will base this surface area on an overflow

rate of 500 gal/day-ft2 in order to design the most efficient sedimentation basin.

The surface area is calculated using the following formula:

A = Qc / O.R.

Where:

A = surface area, ft2

Qc = flow, gal/day

O.R. = overflow rate, gal/day-ft2

In our example, the surface area of one tank is calculated as follows:

A = (500,000 gal/day) / (500 gal/day-ft2)

A = 1,000 ft2

Page 4

(Notice that we converted the flow from 0.5 MGD to 500,000 gal/day before beginning our

calculations.)

3. Volume

The tank volume is calculated just as it was for flocculation basins and flash mix chambers, by

multiplying flow by detention time. The optimal detention time for sedimentation basins

depends on whether sludge removal is automatic or manual.When sludge removal is manual,

detention time should be 6 hours.We will consider a tank with automatic sludge removal, so the

detention time should be 4 hours.

The volume of one of our tanks is calculated as follows:

V = Q t

V = (500,000 gal/day) (4 hr) (1 day/24 hr) (1 ft3/7.48 gal)

V = 11,141 ft3

(Notice the conversions between days and hours and between cubic feet and gallons.)

4. Depth

The tank's depth is calculated as follows:

d = V / A

Where:

d = depth, ft

V = volume, ft3

A = surface area, ft2

For our example, the depth is calculated to be:

d = (11,141 ft3) / (1,000 ft2)

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d = 11.1 ft

The specifications note that the depth should be between 7 and 16 feet.Our calculated depth is

within therecommended range.If the depth was too great, we would begin our calculations

again, using a larger number of tanks.If the depth was too shallow, we would use a smaller

number of tanks.

5. Width and Length

You will remember that the volume of a rectangular solid is calculated as follows:

V = L W d

Where:

V = volume

L = length

W = width

d = depth

For our tank, the length has been defined as follows:

L = 4 W

Combining these two formulas, we get the following formula used to calculate the width of our

tank:

In the case of our example, the tank width is calculated as follows:

W = 15.8 ft

Page 6

The length is calculated as:

L = 4 (15.8 ft)

L = 63.2 ft

6 and 7. Flow Through Velocity

Checking the flow through velocity is done just as it was for the flocculation basin.First, the

cross-sectional area of the tank is calculated:

Ax = W d

Ax = (15.8 ft) (11.1 ft)

Ax = 175.4 ft

2

Then the flow through velocity of the tank is calculated (with a conversion from gallons to cubic

feet and from days to minutes):

V = Qc / Ax

V = (0.0000928 ft3-day/gal-min) (500,000 gal/day) / (175.4 ft2)

V = 0.26 ft/min

The velocity for our example is less than 0.5 ft/min, so it is acceptable.As a result, we do not

need to repeat our calculations.

8. Weir Length

The final step is to calculate the required length of weir.We will assume a weir loading of

15,000 gal/day-ft and use the following equation to calculate the weir length:

Page 7

Lw = Qc / W.L

Where:

Lw = weir length, ft

Qc = flow in one tank, gal/day

W.L. = weir loading, gal/day-ft

So, in our example, the weir length is calculated as follows:

Lw = (500,000 gal/day) / (15,000 gal/day-ft)

Lw = 33.3 ft

The weir length should be 33.3 ft.

Conclusions

Our plant should build a sedimentation tank which is 11.1 feet deep, 15.8 feet wide, and 63.2 feet

long. This tank will have a surface area of 1,000 ft2 and a volume of 11,141 ft3. The flow

through velocity will be 0.26 ft/min. Theweir length will be 33.3 ft.

Review

Sedimentation basin efficiency is influenced by floc characteristics, water temperature, short-

circuiting, gases in the water, algal growth on tank walls, intermittent tank operation, surface

loading, and weir loading. To ensure optimal performance, the operator should test turbidity and

temperature of the water and should visually survey the basin

Design of a sedimentation basin involves the following steps:

· Divide flow into at least two tanks.

· Calculate the required surface area.

· Calculate the required volume.

· Calculate the tank depth.

· Calculate the tank width and length.

· Check flow through velocity.

· If velocity is too high, repeat calculations with more tanks.

Page 8

· Calculate the weir length.

New Formulas Used

To calculate tank surface area:

A = Qc / O.R.

To calculate tank depth:

d = V / A

To calculate width of a rectangular tank where length is four times the width:

To calculate length of a rectangular tank where length is four times the width:

L = 4 W

To calculate flow through velocity:

V = Qc / Ax

To calculate weir length:

Lw = Qc / W.L